(n)/(n+2)=(8)/(n^2-4)+3

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Solution for (n)/(n+2)=(8)/(n^2-4)+3 equation: 



(n)/(n+2)=(8)/(n^2-4)+3

We move all terms to the left:

(n)/(n+2)-((8)/(n^2-4)+3)=0



Domain of the equation: (n+2)!=0

We move all terms containing n to the left, all other terms to the right

n!=-2

n∈R





Domain of the equation: (n^2-4)+3)!=0

n∈R



We calculate fractions

We do not support enpression: n^3

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